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# how to derivative tan(x) and get an answer like sec(x)^2

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how to derivative tan(x) and get an answer like sec(x)^2,same question for sec(x) -> sec(x)tan(x),cot(x)->-csc(x),csc(x)->-csc(x)cot(x)

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This gets you almost there: trigcos(tan(x)') yields 1/cos(x)^2 which is obviously sec(x)^2.

See the manual for many other functions that rewrite trig expressions in various ways. However I don't think there are any which rewrite expressions directly in terms of sec(x), csc(x), or cot(x). The students is expected to learn to recognize those by their definitions, I expect.

Disclaimer: I don't work for HP, but HP calculators work for me.

-Joe-
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thanks for help.

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