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09-13-2015 10:46 AM - edited 09-13-2015 10:49 AM
I've been trying to evaluate a definite integral of a vector, but I believe it is not possible given that the calculator always returns "Bad type argument". Is there any easy way to circumvent it or is there actualy a way to integrate a vector over a finite line?
For reference, the definite integral is: 4/4πε0 ∫(0.1ay-az) /[(.1^2+z^2)^(3/2)]dz from 0 to 0.05
09-13-2015 02:33 PM - edited 09-13-2015 02:42 PM
Thanks for the reply. I tried doing something similar but by 'ay' and 'az' I mean the unit vectors. Upon doing what you say, the z variable in 'az' is reckoned with when integrating with respect to z, which is not my intention. I want it just to be just a vector. In other words, I want essentially to evaluate the integral of the array [0, 0.1, -1] / (0.1 + z^2)^3/2 with respect to z from 0 to 0.05. It should yield say 1.5ay+0.6az and display [0, 1.5,0.6] in HP.
Whenever I try to integrate a vector with the longS function it returns "Bad argument type". The only solution I come up with was to integrate the unit vector ay and az separately, but this will be very tiresome later on. I was hoping there was any easier workaround to this.