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- Need help, what is the max RAM I can put in this HP and how ...

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02-13-2024 10:22 PM
Hello, I just picked up this laptop off a great sale for a decent price and going to run a Linux distro on it.
This are the specs: Product number: 889C1UA Product name: HP Laptop 17-cn0614ds Microprocessor: Intel® Celeron® N4120 (up to 2.6 GHz burst frequency, 4 MB L2 cache, 4 cores, 4 threads) Chipset: Intel® Integrated SoC Memory, standard: 4 GB DDR4-2400 MHz RAM (1 x 4 GB) Video graphics: Intel® UHD Graphics 600 Integrated Hard drive: 128 GB PCIe® NVMe™ M.2 SSD Display: 17.3" diagonal, FHD (1920 x 1080), IPS, anti-glare, 250 nits, 45% NTSC Wireless connectivity: Realtek RTL8822CE 802.11a/b/g/n/ac (2x2) Wi-Fi® and Bluetooth® 5 wireless card External ports: 1 USB Type-C® 5Gbps signaling rate (supports data transfer only and does not support charging or external monitors); 2 USB Type-A 5Gbps signaling rate; 1 AC smart pin; 1 HDMI 1.4b; 1 headphone/microphone combo
What is the limitations of the CPU running Debian as the main OS. Will the limitation of the CPU be able to run Gnome DE?
02-14-2024 07:32 AM - edited 02-14-2024 07:33 AM
Hi:
I can only answer your question regarding the memory.
Notebooks with the Intel Celeron processors have one memory slot and according to the Intel website the processor supports 1 x 8 GB of DDR4-2400 memory.
Intel Celeron Processor N4120 4M Cache up to 2.60 GHz Product Specifications
Now if you want to experiment with a 16 GB memory chip, you can run this command to see if that would be possible:
1. In the search box, search for cmd and click Run as administrator.
This will open the command prompt.
2. After the command prompt is opened, type wmic memphysical get maxcapacityEx and press the enter key.
There, it will show the maximum RAM capacity your PC's motherboard can support.
The capacity is shown as Kilobytes, so you have to convert it to Gigabytes by dividing the number provided in the report by 1,048,576.
If the report returns a 33,xxx,xxx result, then that would be 32 GB total for two slots, as the program will pick up the circuitry for the missing 2nd memory slot.
Thet would mean in theory that a 16 GB DDR4-2400 memory chip should work in the single memory slot.