Guidelines
The HP Community is where owners of HP products, like you, volunteer to help each other find solutions.
Archived This topic has been archived. Information and links in this thread may no longer be available or relevant. If you have a question create a new topic by clicking here and select the appropriate board.
HP Recommended
HP50G

I am trying to graph just part of a polar equation. For example, the equation r = 2 cos (3θ) when graphed will give you a three-petaled flower shape. I need to find the area of just one of the petals, so I need to know what the bounds of each is. What is the best way to go about doing this?

 

Thanks,

10 REPLIES 10
HP Recommended

You can write the equation and plot polar, of three petaled flower and ...

undefined

 

The equation what you indicated, is for a circle.

 

Now, can you indicate what petal you needed find the shape area ?. 

 

See, the Lesson 16, page 32/33, for area, from ... 

HP 50g Tutorial - Thiel College

Kind Regards !.
Have a nice day !.
@Maké (Technical Advisor Premium - HP Program Top Contributor).
Provost in HP Spanish Public Forum ... https://h30467.www3.hp.com/
HP Recommended

Indeed, I meant 2 cos (3θ). I need to find the area of any one of the petals, but may also need to find the areas of cardiods and other shapes.

HP Recommended

Been a while since I've done this, but don't you just need to do:

 

int(1/2*(<your_function>)^2, <var> , <start>, <finish> ) 

 

example:

 

∫((1/2)*(2*cos(3*θ))^2,θ,0,π/3)  => ~1.047...

 

 

For any of them? If it converges, you should be good I think.

TW

Although I work for the HP calculator group as a head developer of the HP Prime, the views and opinions I post here are my own.
HP Recommended

Hello,

The problem is, I am not given the start and end points, otherwise that would be exactly what I would do.

HP Recommended

You needed calculate, the area, of one petal, of ... https://math.stackexchange.com/questions/328744/find-the-area-of-the-roses-petal

 

undefined

 

undefined

 

Kind Regards !.
Have a nice day !.
@Maké (Technical Advisor Premium - HP Program Top Contributor).
Provost in HP Spanish Public Forum ... https://h30467.www3.hp.com/
HP Recommended

Hi,

 

When you have the three petal shape in the plot window select  TRACE (F3) then (X,Y) (F2), you should now see θ and Y co-ordinates at the bottom of the screen.

 

Use the left & right buttons to step round the graph and find the co-ordinates of the required points.

To export co-ordinate values to the stack:

press a function key to see the menu again

select EDIT and press NXT twice then select X,Y->

Select PICT and  (X,Y) to go back to finding co-ordinates (TRACE should still be active)

When you exit graph mode the values will be on the stack.

 

Then use the θ values in the method in Tim Wessman's reply to find the area.

 

 

-Bart
_________________________________________________________
calculator enthusiast
HP Recommended

Hi!, @RallyToMe:

 

See, the Lesson 16, page 32/33, for area, from ... 

HP 50g Tutorial - Thiel College

Kind Regards !.
Have a nice day !.
@Maké (Technical Advisor Premium - HP Program Top Contributor).
Provost in HP Spanish Public Forum ... https://h30467.www3.hp.com/
HP Recommended

@Maké wrote:

@hi!, @RallyToMe:

 

See, the Lesson 16, page 32/33, for area, from ... 

HP 50g Tutorial - Thiel College


 

 

However please note that  FCN  is not available in Polar plots, but it is indeed very useful for Function plots.

 

 

-Bart
_________________________________________________________
calculator enthusiast
HP Recommended

In addition to which has been said already:

 

A petal begins when r=0 and ends when r=0 again.

 

So you have to integrate from one zero of r(θ) to another zero of r(θ).

 

The zeros of cos(3θ) are: 3θ=π/2+n.π,

so θ= π/6+ π/3.n

 

So you could integrate from π/6 to π/6+ π/3

 

This is the corresponding petal for this range and “auto” pressed in the menu of Plot Window

undefined

Archived This topic has been archived. Information and links in this thread may no longer be available or relevant. If you have a question create a new topic by clicking here and select the appropriate board.
† The opinions expressed above are the personal opinions of the authors, not of HP. By using this site, you accept the <a href="https://www8.hp.com/us/en/terms-of-use.html" class="udrlinesmall">Terms of Use</a> and <a href="/t5/custom/page/page-id/hp.rulespage" class="udrlinesmall"> Rules of Participation</a>.