Can I upgrade my RAM from 8GB to 16GB without voiding warranty

[Jules333]

I have an HP Envy notbook Serial No. [edited] ProductNo. Y4A48AV. Is it capible from upgrading from 8GB of RAM to 16GB? I bought it in July of 2017. Would upgrading void my warrenty?

Thank you for your time. 

[Riddle_Decipher]

@Jules333

Thank you for posting on HP Forums, 

Riddle_Decipher is at your service. 

As I understand you want to upgrade the memory modules on your pc,

No worries, as I'll be glad to help you, that said, I'll need a few more details to dissect your concern & provide an accurate solution: 

Did you check the service and maintenance guide?

While you respond to that, here's what you need to know:

Click here for the maintenance guide

Two memory slots, non accessible

Support for DDR3L-1600

Dual Channel

Support for up to 16-GB maximum on-board system memory

● 16384 MB (8192 MB × 2)

● 12288 MB (8192 MB + 4096 MB)

● 8192 MB (8192 MB × 1)

● 8192 MB (4096 MB × 2)

And to answer your question, no they do not void the warranty,

Let me know how that pans out

feel free to give me a virtual high-five by clicking the 'Thumbs Up' icon,

followed by clicking on 'Accepted as Solution' as it would help the community gain more knowledge,

And Have a great day Ahead!

[Huffer · Accepted solution]

So after all that, the answer to your question is "no" in case you did not get that. 8 gigs is the max apparently. 

Except when it is not. You have the 17t-s100 model and here is the manual:

Manual

Support for DDR3L-1600 Dual Channel Support for up to 16-GB maximum on-board system memory ● 16384 MB (8192 MB × 2)

So the ACTUAL answer is yes of course you can upgrade to 16 gigs without affecting your warranty. 

You need 2 of these:

Memory modules (2; PC3L, 12800, 1600-MHz): 8 GB 693374-005

Read pages 28-36 of the manual for "how to". 

If in the USA get 2 of these and install or just one if you already have one 8 gig module:

https://www.amazon.com/Kingston-Technology-1600MHz-PC3-12800-KVR16LS11/dp/B00CQ35HBQ/ref=sr_1_1?ie=U...

Post back with any more questions.

If this is "the Answer" please click "Accept as Solution" to help others find it.