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Archived This topic has been archived. Information and links in this thread may no longer be available or relevant. If you have a question create a new topic by clicking here and select the appropriate board.
HP Recommended

Good day everyone!

 

I can't figure out how to do implicit differentiation and logarithmic differentiation on the Prime.

For instance, I am trying to find y' for this equation.  

 

x^2 + y^2 = ln (x + y)^2

 

Solving the question manually, I know that the answer is 

 

y'= (-x^2 - xy + ln(x + y)) / (y^2 + x y - ln(x + y))

 

I hope you can help me please!

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
HP Recommended

Hello,

 

There is no specific command for it. Basically, this is the steps:

 

1. Put everything on one side

2. Store as a variable

3. dx/dy

 

Example:

 

eq:=x^2 + y^2 - ln (x + y)^2

eq'/(eq,y)'   (  or diff(eq)/diff(eq,y)  )

 

Then simplify your result.

 

TW

Although I work for the HP calculator group as a head developer of the HP Prime, the views and opinions I post here are my own.

View solution in original post

3 REPLIES 3
HP Recommended

Hello,

 

There is no specific command for it. Basically, this is the steps:

 

1. Put everything on one side

2. Store as a variable

3. dx/dy

 

Example:

 

eq:=x^2 + y^2 - ln (x + y)^2

eq'/(eq,y)'   (  or diff(eq)/diff(eq,y)  )

 

Then simplify your result.

 

TW

Although I work for the HP calculator group as a head developer of the HP Prime, the views and opinions I post here are my own.
HP Recommended

Thanks a lot Tim!

 

Now, all I need to do is explore this Prime even more.

HP Recommended

I would also like to communicate my interest in this functionality. Coming from a background with TI calculators, this has been supported natively since the TI-89. 

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